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navik [9.2K]
2 years ago
6

Find w. A. 8.9 B. 0.05 C. 0.08 D. 5.2

Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

Step-by-step explanation:

Measure of angle V = 180 - 62 - 36 = 82 degrees

So by the law of sines, 10/sin(82 deg) = w/sin(62 deg)

w = [10sin(62)]/sin(82)

from here just plug this into a calculator

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A painting measure 40 cm by 35 cm how many squared cm does its surface cover
miskamm [114]

Answer: Its surface covers  1400 cm²

Explanation:

Since the length of painting = 40 cm

Breadth of painting = 35 cm

Since we know that area of rectangle is product of dimensions.

∴ Area of painting = length × breadth

= 40 cm × 35 cm

= 1400 cm²

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8 0
3 years ago
Find the Sum.<br> 213,857 +43,762
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Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

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