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navik [9.2K]
2 years ago
6

Find w. A. 8.9 B. 0.05 C. 0.08 D. 5.2

Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

Step-by-step explanation:

Measure of angle V = 180 - 62 - 36 = 82 degrees

So by the law of sines, 10/sin(82 deg) = w/sin(62 deg)

w = [10sin(62)]/sin(82)

from here just plug this into a calculator

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Factor completely. x2 −3x−40 Enter your answer in the box.
Aleks [24]

Answer:

(x - 8) (x + 5)

Step-by-step explanation:

You want to start with breaking down -40 to find the integers that will go into that, which are 8 and 5. Then you take the knowledge of 8 and 5 and turn your attention to -3x.

8 and 5 must be added together to equal -3x. 8 is the larger number so it must be the negative in the equation and be must be the positive. Thus it would be -8x + 5x = -3x

Knowing that, is it simple to break x^2 because it is simply x * x = x^2

5 0
4 years ago
Read 2 more answers
If X-1 = 2<br> Work out the value of 2x2
amid [387]

Answer:

2x

2

−x−2=2(−1)

2

−(−1)−2 [Putting x=−1]

=2×1+1−2=2+1−2

=3−2

=1.

5 0
3 years ago
Is y=1/x proportional
coldgirl [10]

Answer:

we say that they are inversely propotional

Step-by-step explanation:

5 0
3 years ago
The sum of two numbers is 21. the second number is six times the first number . Work out the two numbers
jeyben [28]

Answer:

3 and 6

Step-by-step explanation:

3*6=18

18+3=21

7 0
3 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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