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lesya [120]
2 years ago
13

Can someone please help me with this

Mathematics
2 answers:
lapo4ka [179]2 years ago
7 0

Answer:

1. (3,5)

2. B

Not sure for the second one but try it

Lubov Fominskaja [6]2 years ago
3 0

Answer:

10) C

11) A

Step-by-step explanation:

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Evaluate 6 over 3 plus 7 times 4
ehidna [41]

the answer is B. 244

5 0
4 years ago
Question 2 (2 points)<br> Subtract.<br> A) -18 - (-12) =<br> on &amp;<br> 5
muminat

Answer:

-6

(I don’t understand what you mean by on & 5 but..)

Step-by-step explanation:

The two negatives (the -(- ) cancel each other out and make a postive, so

-18 + 12 = -6

7 0
3 years ago
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A: x/4 +1 = -3 B: x+4 = -12 1) How can we get Equation B from Equation A?
Sveta_85 [38]

Answer:In the equation y = mx + b for a straight line, the number m is called the slope of the line. Let x = 0, then y = m • 0 + b, so y = b. The number b is the coordinate on the y-axis where the graph crosses the y-axi

Step-by-step explanation:

5 0
3 years ago
Write an equation to represent the relationship between the number of mugs and cost for company A. Use c for cost and m for the
ss7ja [257]

Answer:

Assuming this is a linear problem, the equation would look like this:

C(m)=Mx

Step-by-step explanation:

Because you don't have any other details, this as much of an answer I can give you. The cost for the company depends on how many mugs they produce. If the cost for making a mug is 3 dollars, then m would be that value, and x would be the amount of mugs you're trying to make.

3 0
3 years ago
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On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th
Schach [20]

Answer:

Average speed   is 37.35 mi/h

Step-by-step explanation:

given data

leave =  34 minutes before

church distance =  12.0 miles

average speed first 17 minutes =  5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × \frac{17}{60}

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed  = \frac{distance}{time}

Average speed  = \frac{10.584}{\frac{17}{60}}

Average speed   is 37.35 mi/h

3 0
3 years ago
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