Pretend * is counter
* * *
* * *
the word problem could be in a box of chocolates there is 3 rows and 2 chocolates in each row how many chocolates are there total.
256-192= 64
192-144=48
144-108=36
108-81=27
81- 60.8=20.2
60.8-45.6=15.2
45.6-34.2= 11.4
34.2-25.6=8.6
25.6-19.2= 6.4
19.2-14.4= 4.8
4x + 2x + 2
= 6x + 2
So the answer is B
Chocolate thickshakes will cost $5 and fruit smoothies will cost $3. Let's say the cost of chocolate thickshakes are x and the cost of fruit smoothies are y.
3x + 4y = 27
3x + 3y = 24
<span>Solve for d.
5+d>5−d Subtract 5 from both sides of this inequality:
d>d There is no value for d that satisfies this inequality.
No value can be greater than itself.
</span><span>Solve for p.
2p+3>2(p−3) Multiply this out: 2p+3>2p-6
</span><span> Subtr 3 from both sides: 2p> 2p-9
This is equivalent to 2p+9>2p.
We could subtr. 2p from both sides: 0>-9.
0> -9 is always true. Thus, the given inequality has infinitely many solutions.
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