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Nuetrik [128]
2 years ago
6

7.209 x 10 -4 in standard form

Mathematics
1 answer:
astraxan [27]2 years ago
6 0

\huge\textbf{Hey there!}

\mathsf{7.209\times10^{-4}}\\\\\mathsf{\approx 7.209\times\dfrac{1}{10\times10\times10\times10}}\\\\\mathsf{\approx 0.000721}\\\\\mathsf{\approx  7.21\times10^{-4}}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{7.21\times10^{-4}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}

~\frak{Amphitrite1040:)}

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A research report claims that mice with an average life span of 32 months will live to be about 40 months old when​ 40% of the c
makvit [3.9K]

Answer:

t=\frac{39-40}{\frac{8.8}{\sqrt{70}}}=-0.9508      

p_v =P(t_{69}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly less than 40 months.

Step-by-step explanation:

1) Data given and notation      

\bar X=39 represent the sample mean

s=8.8 represent the standard deviation for the sample      

n=70 sample size      

\mu_o =40 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean  is less than 40 months, the system of hypothesis would be:      

Null hypothesis:\mu \geq 40      

Alternative hypothesis:\mu < 40      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{39-40}{\frac{8.8}{\sqrt{70}}}=-0.9508      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=70-1=69  

Since is a one-side lower test the p value would be:      

p_v =P(t_{69}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly less than 40 months.      

5 0
4 years ago
Each student in a class recorded how many books they read during the summer. Here is a box plot that summarizes their data. What
Readme [11.4K]

Answer:

15

Step-by-step explanation:

.

4 0
4 years ago
125. Albert surveyed a class of 25 students on sports. 5 kids love baseball. 7 kids love basketball. 10 kids
MAXImum [283]

Answer:

3 students

Step-by-step explanation:

since the<em> </em>total number of students is 25,when you add those that like baseball, basketball and football the total number must be 25 but in this case it's 22 meaning 2 student liked neither.

7+5+10+x=25

x=25-22

=3

I hope this helps

4 0
4 years ago
Can someone help me with this I don’t understand
zloy xaker [14]
You have to use formula of combination
there are 13 heart in deck and 52 number of card in deck
now,
to find the probability that we choose two heart from deck , we use below formula
c \binom{13}{2}  \div c \binom{52}{2}
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8 0
4 years ago
A ship is stationary at sea.
Andrei [34K]

Answer:

The distance between the yacht from the ship is about 33.6 km.

Step-by-step explanation:

The diagram is attached below.

Point A is the shipe, Point B is the tugboat, and Point C is the yacht.

Since the tugboat is 28 km away, and the scale being used is 1 cm : 4 km, the tugboat is 7 cm away from the ship at a 210° bearing on the diagram.

Likewise, the yacht is 6 cm away from the tugboat at a 210° bearing.

To find the distance between the yacht to the ship, we need to determine the value of <em>x</em>.

To do so, we can use the Law of Cosines:

b^2=a^2+c^2-2ac\cos(B)

First, we need to determine ∠B.

A has a bearing of 210°. 180° is covered by QI and IV. So, the small angle in QIII is 30°.

By Alternate Interior Angles, the angle in QI (inside the triangle) of Point B must also be 30°.

And since Point B has a bearing of 310°, 270° is covered in total by QI, QIV, and QIII. So, 40° is left in QII.

Therefore, 50° is the measure of the angle in QIII within the triangle of Point B.

Thus, ∠B measures 50° + 30° = 80°.

So, ∠B measures 80°. We also know that <em>a</em> = 6 and <em>c</em> = 7. Substitute:

b^2=(6)^2+(7)^2-2(6)(7)\cos(80)

Simplify and take the square root of both sides. So:

b=\sqrt{85-84\cos(80)}

Approximate using a calculator:

b=8.3912...\approx 8.39\text{ cm}

Since 1 cm : 4km, to find the distance in km, we simply need to multiply by four. So:

\Rightarrow b=4(8.3912...)=33.5651\approx 33.6\text{ km}

The distance between the yacht from the ship is about 33.6 km.

7 0
3 years ago
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