Step-by-step explanation:
∆TSU=∆RSU (SAS).
HENCE,
NONe of the above statement is true.
Answer:
the inverse for each relation:
1. {(1,-2), (2, 3),(3, -3),(4, 2)} is
<u>{</u><u>(</u><u>-</u><u>2</u><u>,</u><u>1</u><u>)</u><u>,</u><u>(</u><u>3</u><u>,</u><u>2</u><u>)</u><u>,</u><u>(</u><u>-</u><u>3</u><u>,</u><u>3</u><u>)</u><u>,</u><u>(</u><u>2</u><u>,</u><u>4</u><u>)</u><u>}</u><u>.</u>
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
80.4
Step-by-step explanation:
21.03 + 80.4 - 21.03
21.03 - 21.03 cancel each other out because it equals 0.
The equation becomes 0 + 80.4 = 80.4