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4 years ago

Please answer this question fast in two minutes

Mathematics

2 answers:

navik [9.2K]4 years ago

7 0

Answer:

132 degree

Step-by-step explanation: angle kjh is 132 degree and since lk is a straight line it is 180 degree. angle kjh is 132 degree so, angle LJM is 132 degree. This is because adjacent angles are equal as you can see, Angle LJM is adjacent to Angle KJH.

inessss [21]4 years ago

3 0

ANSWER:
It is given that angle KJH=132degrees
And we need to find angle IJM
Angle IJM=132 degrees ( vertically opposite angles)
HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!!

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Find the missing sides.<br> (Help me)

slavikrds [6]

Answer:

2nd one

Step-by-step explanation:

when it's a 45 45 and 90 triangle, it's 1, 1, sqrt 2, but now since the 1 is sqrt 2, v is sqrt 2, and u and sqrt 2 times sqrt 2, which is 2

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3 years ago

Find the greatest common factor of 270 and 360. (Give the answer in the numerical form in the top box and in exponential form by

Kipish [7]

Answer:

Step-by-step explanation:

The factors of 270 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270

The factors of 360 are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360

Then the greatest common factor is 90.

5 0

3 years ago

Read 2 more answers

2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00

svlad2 [7]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

55% of the students live within five miles of you, thus $p = 0.55$ .

Item a:

This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125$

$p = 0.091125(0.55) = 0.0501$

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

$E = \frac{q}{p}$

In this problem, $p = 0.55$ , and 1 trial, thus $q = 1$ , hence:

$E = \frac{1}{0.55} = 1.82$

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

$S = \frac{\sqrt{q(1 - p)}}{p}$

Hence, since $q = 1, p = 0.55$ :

$S = \frac{\sqrt{0.45}}{0.55} = 1.22$

The standard deviation is of 1.22 students.

Item d:

This probability is $P(X = 3)$ when $n = 5$ , hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369$

There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

$E(X) = np$

Hence, since $n = 5, p = 0.55$ :

$E(X) = 5(0.55) = 2,75$

It is expected that 2.75 students live within five miles of you.

A similar problem is given at brainly.com/question/25343741

7 0

3 years ago

HALP PLAEZ IM STRUGGLING<br> brainliest to whoever answers them all!

makvit [3.9K]

Answer:

1. 440:44, songs Per CD: 10

2. 140:5, pieces per bag: 28

3. 30:6, Customers per lane: 5

4. 290:10, students per class: 29

5. 161:7, cans per bag: 28

6. 324:18, tickets per person: 18

7. 90:5, containers per day: 18

8. $80:4, Dollars per ticket: 20

9. 15:3, ice cubes per tray: 5

10. 24:6, buttons per controller: 4

11. 335:67, dollars per shirt: 5

12. 14:2, pies per minute: 7

13. 80:8, dollars per student: 10

Step-by-step explanation:

<em>You put the largest number at the front and divide. For example, 80 ÷ 8 = 10 there you have the rate. Hope this helps! :D</em>

8 0

3 years ago

I really need help, I’m having a quiz tomorrow yet I struggle to understand the concept of this stuff...

uranmaximum [27]

Here it goes:

a. Because you have four blue marbles out of the 12 total marbles, the probability is 4/12. YOU MUST SIMPLIFY down to 1/3.

b. There are 12 marbles in the bag right now, and the probability is 4/12, you must add some marbles. 1/10 multiplied by 4 is 4/40. There are 4 blue marbles right now, and 40 minus the 12 there are right now is 38, so you would need to add 38 non-blue marbles.

3 0

3 years ago