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ale4655 [162]
3 years ago
6

Malik upgrades his cell phone. He will pay a $35 activation fee and $40 per month for service write an expression for the cost o

f m months
Mathematics
1 answer:
Doss [256]3 years ago
7 0
Answer:
$35 + $40M
Step-by-step explanation:
A cell phone company charges per month fees
$40
and an activation fee =$35
Total cost = Activation fees + ($40 × total
number of months)
So the expression for the total cost for M
months will be
$35 + $40M
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Step-by-step explanation:

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Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

Hence, the derivative of the given function is \dfrac{2x^2-1}{x(x^2-1)} .

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Step-by-step explanation:

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