radius* 2=diameter so no diameter and radius aren't the same thing because radius is half the distance across the circle and diameter is the full distance across the circle.
The fraction symbolizes division. Divide, buddy.
Answer:
y = x - 13
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 9 ← is in slope- intercept form
with slope m = 1
Parallel lines have equal slopes, thus
y = x + c ← is the partial equation of the parallel line
To find c substitute (6, - 7) into the partial equation
- 7 = 6 + c ⇒ c = - 7 - 6 = - 13
y = x - 13 ← equation of parallel line
Answer:
Option C) The symbol y represents the predicted value of price.
Step-by-step explanation:
We are given the following in the question:
We find a regression equation with x representing the ratings and y representing price.
The equation has a slope of 130 and a y-intercept of 350.
Comparing with the slope intercept form:
Thus, we can write the equation as:
Here, y is the predicted variable that is the price, c is the price of hotel when a rating of 0 is given.
Thus, symbol y represents:
C) The symbol y represents the predicted value of price.
The perimeter "P" is equal to the length of the base of one triangle multiplied by the "n" number of triangles in the figure plus two times the length of another side. The equation for the perimeter is P = 5n + 14.
We are given triangles. The triangles are arranged in a certain pattern. The length of the base of each triangle is equal to 5 units. The length of the other two sides is 7 units each. We conclude that all the triangles are isosceles. We need to find the relationship between the number of triangles and the perimeter of the figure. Let the perimeter of the figure having "n" number of triangles be represented by the variable "P".
P(1) = 14 + 5(1)
P(2) = 14 + 5(2)
P(3) = 14 + 5(3)
We can see and continue the pattern. The relationship between the perimeter and the number of triangles is given below.
P(n) = 14 + 5n
To learn more about perimeter, visit :
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