In order to solve this mathematical problem we can first
consolidate and observe the given values and the values that are not known in
the stated problem.
Annie traveled 5 times the sum of the number of hours Brian
traveled and 2. Together they traveled 20 hours. Find the numbers.
Equation,
<span><span>
1. </span><span> 5(y) + 2 = 20</span></span>
<span><span>2. </span><span> 5y = 20 – 2</span></span>
<span><span>
3. </span><span> 5y = 18</span></span>
<span><span>4. </span><span> Y = 18 / 5</span></span>
<span><span>
5. </span><span> Y = 3.6</span></span>
<span><span>
6. </span><span> 5y = 5(3.6)</span></span>
<span><span>
7. </span><span> Annie = 18</span></span>
Hence, Annie traveled 18 hours while Brian traveled 3.6
hours.
Okay so form a right angle triangle and the angle of that is 65 as it is right angle so 90 - 25= 65. label the sides like the pic below.
we have the hypothenuse as well as the angle and we are trying to find the o(opposite side)
o/h =sin
sin 65=23/h
sin 65 = 23/x
23/sin 65=x
x=25.4
how high the kite is above ground is :
= 25.4 +1.2
=26.6
Answer:
B and C
Step-by-step explanation:
We can just solve each to find which expressions are equal to 1.5.
A) 0.15 × 100 = 15
B) 15.0 ÷ 10 = 1.5
C) 0.15 × 10 = 1.5
D) 0.15 ÷ 10 = 0.015
E) 1.5 ÷ 100 = 0.015
From our results, we see that B and C are the only answers that equal 1.5.
Answer:
2 1/2 dollars per side
Step-by-step explanation:
7 + 5 is 12 so half of five ( 5$ is the price of two sides ) is 2 1/2 and 2 1/2 is the price of one side.
( sorry if it is confusing ^O^ )
Answer:
54 sq units
Step-by-step explanation:
The triangle at the top (FAB) has a base of 10 and a height of 3. Area of triangle is 1/2bh so 1/2(10 * 3) = 1/2 * 30 = 15 sq units
If you cut off the triangle you have a trapezoid, EBCD. A trapezoid is (b1 + b2)/2 * h, so (6 + 7)/2 * 6 = 13/2 * 6 = 6.5 * 6 = 39 sq units
Add them together: 15 + 39 = 54 sq units
