Answer:
The inequality should be written as $2.50 times c is greater than or equal to c.
Step-by-step explanation:
First, identify what you know:
1) Each chocolate bar is $2.50
2) Sebastian needs to raise at least $500
So, Sebastian needs to sell at least enough chocolate bars to hit $500. The inequality cannot be written as less than or equal to, because he can't sell less than the number of chocolate bars needed to make $500.
Automatically, I can calculate the minimum number of bars he'll need to sell.
500/2.50 = 200 chocolate bars minimum
c must equal greater than or equal to $500, for Sebastian to raise enough money! So, basically Sebastian has to sell 200 bars OR more.
Hope this helps! :)
Together they mowed 1565 11/50 square yards. You have to make the fractions have same denominators so you can add, after fixing the denominators, just add.
The confidence interval is

.
We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.
Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.
To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.
The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.
Thus the confidence interval is 77.28 +/ 2.23.
Answer:
Step-by-step explanation:
a) a = 2*2.99- (2.99 +1.49)
a = 5.98 - 4.48
a = $1.50
r = 2* 3.99 - (3.99 + 2.49)
r = 7.98 - 6.48
r = $ 1.50
B) Both fruits has the same discount.
Answer: (0.120,0.160)
Step-by-step explanation:
Given : Sample size : 
Number of disks were not defective =701
Then , the number of disks which are defective = 
Now, the proportion of disks which are defective : 
Significance level : 
Critical value : 
The confidence interval for population proportion is given by :-

Hence, the 90% confidence interval for the population proportion of disks which are defective = (0.120,0.160)