If the line is parallel, you know it’s going to have the same slope, which in this case is 3
Using the format y= mx + b, plug in your x and y values to find b (m is the slope)
-11 = 3(-4) + b
-11= -12 + b
b = 1
You now have all the needed values to write the equation in slope-intercept form:
y = 3x + 1
Answer:
Option A:
x^2 + (y - 2)^2 = 9
Step-by-step explanation:
We know that the equation for a circle centered in the point (a, b) and of radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
So the first thing we need to find is the center of the circle.
We can see that the center is at:
x = 0
y = 2
Then the center is at the point (0, 2)
Now we want our circle to pass through point 2, located at a distance of 2 units from the radius of the first circle.
So the distance between the center and point 2 is 2 units plus the radius of the smaller circle:
And the radius of the smaller circle is one unit.
Then, the radius of a circle centered at (0, 2) that passes through point 2 is:
R = 1 + 2 = 3
Then we have a circle centered at (0, 2) and of radius R = 3
Replacing these in the equation for a circle we get:
(x - 0)^2 + (y - 2)^2 = 3^2
x^2 + (y - 2)^2 = 9
The correct option is A
Y = a number
"is" means "equal to"
Equation:
Y - 8 = 94
Solving for Y:
Y - 8 = 94
Add 8 to both sides
Y = 102
Answer: Y = 102
Hope this helps!!
(11,1) because if you plug in x and y this answer is the only one that gives you 18 in the end
-15+7=-8
Adding numbers with different signs makes it subtraction and the answer will have the sign of the bigger number