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lord [1]
3 years ago
6

Awnser the following question:

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
3 0
In this case, you need ro do 4 ÷ 1/3, which is equal to 4 × 3, which equals 12.
He will have 12 sections on the poster board
Nadusha1986 [10]3 years ago
3 0
It's simple, all you do is a model and demonstrate how 1/3 is divided by 4 which will lead you to 12 equal sections and that's how you find the answer
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Stu trained for a triathlon for 5 hours yesterday. He ran 5 miles and then biked 80 miles. His biking speed is 15 mph faster tha
lara31 [8.8K]

Answer:

Step-by-step explanation:

Given as :

The distance cover while running = D_1 = 5 miles

Let The speed for running = S_1

The distance cover with bike = D_2 = 80 miles

The speed for biking = S_2 = 15 mph +  S_1

Total Time taken = 5 hours

Now Time = \dfrac{\textrm Distance}{\textrm Speed}

∴ 5 hour = \frac{D_1}{S_1} +  \frac{D_2}{S_2}

Or,  5 hour = \frac{5}{S_1} +  \frac{80}{15+S_1}

Or, 5 hour = \frac{75 + 5 S_1 + 80 S_1}{S_1(15+S_1)}

or,  5 × (S_1^{2}+15 S_1) = 85 S_1 + 75

Or, 5 S_1^{2} + 75 S_1 -  85 S_1 - 75 = 0

or, 5 S_1^{2} -10 S_1 - 75 = 0

or,   S_1^{2} -2 S_1 - 15 = 0

Or, S_1^{2} -3 S_1 + 5 S_1- 15 = 0

Or, S_1 (S_1 - 3) + 5 (S_1 - 3) = 0

Or, (S_1 - 3) ( S_1 + 5 ) = 0

∴ S_1 = 3 , - 5

So, the running speed = 3 mile per hour

And the biking speed = 15 mph + 3 mph = 18 mile per hour

Hence The running speed of Stu is 3 mile per hour  .  Answer

7 0
3 years ago
1)Circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1)(2, 1) and has a radiu
galina1969 [7]

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = \pi.r^{2}\alpha÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

8 0
3 years ago
I have a whole packet :(
Maslowich
12 A . my guess would be to divide 2175 by 18 which would give you 120.83
7 0
3 years ago
What is the domain and range of the function f(x) = x^2 -4x-5?
Tems11 [23]
F(x) = x²-4x-5, quadratic function,  
Domain (the values if x) is all real numbers.

To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up.  Minimum value of y =-9
Range(the values of y) is [-9, ∞)


5 0
3 years ago
Daniel's father worries that his son is not a motivated student, especially after observing his study habits for a week.
lesya [120]
The answer would be C because he did not correct his mistakes that he had made
4 0
3 years ago
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