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Vikentia [17]
3 years ago
10

PLEASE HELP

Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

The answer is 15 square ft

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4x-5.2y + 6y + 7.9x - 8x
Ipatiy [6.2K]

Answer:

3.9x + 0.8y

Step-by-step explanation:

this is your answer

5 0
3 years ago
Geometry math question no Guessing and Please show work
yawa3891 [41]
A

So, first we look at the equations
y= (x+3)^2+4 changes to
y= (x+1)^2+ 6

So, the first one is saying that we start at (-3,4)
(since when in the parentheses, it's opposite) and the second one is saying start at (-1,6), so it moved on the x-axis 2 units to the right and on the y-axis, it moved 2 units up
4 0
3 years ago
Read 2 more answers
The slope of a line is -5. What is the rise if the run is 4?
MA_775_DIABLO [31]

Answer:

-1.25

Step-by-step explanation:

-5=X/4

-5(4)=-1.25

6 0
3 years ago
Read 2 more answers
What is the vertex of a parabola defined by the equation <br> x = 5y2?
QveST [7]

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

3 0
3 years ago
Help me out fast pleaseeeeeeeeeeeeeee
boyakko [2]

Answer:

81 7/12

Step-by-step explanation:

75 5/12 - (-6 1/6)= 81 7/12

8 0
3 years ago
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