Question

Please Help!! I will mark brainliest for the correct answer!!

Answer 1

Step-by-step explanation:

Please Help!! I will mark brainliest for the correct answer!!

A parabola has its vertex at (2, -3) and its y-intercept at (0,5)

Write an equation of the parabola in the form y= a(x-h)^2+k

Answer 2

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\stackrel{vertex}{(\stackrel{h}{2}~~,~~\stackrel{k}{-3})}\qquad y=a(x-2)^2-3~\hfill \textit{we also know that} \begin{cases} x=0\\ y=5 \end{cases} \\\\\\ 5=a(0-2)^2-3\implies 5=4a-3\implies 8=4a\implies \cfrac{8}{4}=a\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=2(x-2)^2-3~\hfill$