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3 years ago

HELPPPPPPPPPP please this test too much for me

Mathematics

1 answer:

valkas [14]3 years ago

8 0

Answer:

It would be the second graph.

Step-by-step explanation:

Congruent means (of figures) identical in form; coinciding exactly when superimposed. So when you do the translations they will be the exact same.

Hope this helps

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How can i get help with alegbra 2

disa [49]

Watch videos on YouTube, that's what I do with geometry.

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3 years ago

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The total cost (in dollars) for a company to manufacture and sell x items per week is C=40x+180, whereas the revenue brought in

crimeas [40]

Answer:

The company needs to sell either 30 or 40 items.

Step-by-step explanation:

We are given that the cost for selling x items given by the function:

$C(x)=40x+180$

And the revenue for selling x items is given by:

$R(x)=68x-0.4x^2$

The profit function is the cost function subtracted from the revenue function:

$P(x)=R(x)-C(x)$

Substitute and simplify:

$\displaystyle \begin{aligned} P(x)&=(68x-0.4x^2)-(40x+180)\\&=68x-0.4x^2-40x-180\\&=-0.4x^2+28x-180\end{aligned}$

To find how many items must be sold in order to obtain a weekly profit of $300, we can let P equal 300 and solve for x. So:

$300=-0.4x^2+28x-180$

Solve for x. Subtract 300 from both sides:

$-0.4x^2+28x-480=0$

We can divide both sides by -0.4:

$x^2-70x+1200=0$

Factor:

$(x-40)(x-30)=0$

Zero Product Property:

$x-40=0\text{ or } x-30=0$

Solve for each case:

$x=40\text{ or } x=30$

So, in order to obtain a weekly profit of $300, the company need to sell either 30 or 40 items.

7 0

3 years ago

The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

4 0

3 years ago

PROBABILITY!!!!! If you answer ALL you get 40 points and marked BRAINLIEST!!!!!!!

Gekata [30.6K]

Answer:

Step-by-step explanation:

The first one is 18/40, which reduced to lowest terms, is 9/20.

3/4

28/40, which reduced to lowest terms, is 7/10

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What is the first step in solving the equation 2/3x + 1/3x + 2 =5

Sonbull [250]

You need to add like term,
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x + 2 = 5
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x = 5-2

x = 3

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3 years ago

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