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2 years ago

Find the Area please help me

Mathematics

1 answer:

Serggg [28]2 years ago

7 0

Step-by-step explanation:

Area for a right angle triangle = 1/2 bh

b = Base

h = Height

A = 1/2×bh

= 1/2 × 2c^3d^2 × 4c

= (2c^3d^2 × 4c) / 2

= c^3d^2 × 2c

= 2c^4 × d^2

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The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past

galina1969 [7]

Complete Question

The complete question is shown on the uploaded image

Answer:

1 ) The correct option B

2) The correct option is C

3) The correct option is C

4) The correct option is C

Step-by-step explanation:

From the question we are told that

The proportion that own a cell phone is $p = 0.90$

The sample size is n = 15

Generally the appropriate distribution for X is mathematically represented as

$X \ is \ B( n , p )$

$X \ is \ B( 15 , 0.90 )$

Generally the number students that own a cell phone in a simple random sample of 15 students is mathematically represented as

$\mu = n * p$

$\mu = 15 * 0.90$

$\mu = 13.5$

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

$\sigma = \sqrt{ n * p * q }$

Where q is mathematically evaluated as

$q = 1- p$

$q = 1- 0.90$

$q = 0.10$

$\sigma = \sqrt{ 15 * 0.90 * 0.10 }$

$\sigma = 1.16$

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * p^{15} * q^{15 - 15}$

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * (0.90)^{15} * (0.10 )^{15 - 15}$

From the combination calculator is $\left 15} \atop {}} \right.C_{15} = 1$

$P(X = 15) = 1 * 0.205891 * 1$

$P(X = 15) = 0.206$

7 0

3 years ago

Find the sum of the first 20 terms of the arithmetic sequence 4, -4, -12, -20

Vsevolod [243]

Answer:

The sum of the first 20 terms is -1440.

Step-by-step explanation:

We want to find the sum of the first 20 terms of the arithmetic sequence:

4, -4, -12, -20...

The sum of an arithmetic sequence is given by:

$\displaystyle S=\frac{k}{2}(a+x_k)$

Where k is the number of terms, a is the initial term, and x_k is the last term.

Since we want to find the sum of the first 20 terms, k = 20.

Our initial term a is 4.

Our last term is also the 20th term as we want the sum of the first 20 terms.

To find the 20th term, we can write an explicit formula for our sequence. The explicit formula for an arithmetic sequence is given by:

$x_n=a+d(n-1)$

Where a is the initial term, d is the common difference, and n is the nth term.

Our initial term is 4. From the sequence, we can see that our common difference is -8 since each subsequent term is eight less than the previous term. Therefore:

$x_n=4-8(n-1)$

Then the last or 20th term is:

$x_{20}=4-8(20-1)=4-8(19)=-148$

Therefore, the sum of the first 20 terms are:

$\displaystyle\begin{aligned} S_{20}&=\frac{(20)}{2}\left((4)+(-148))\\&=10(-144) \\&= -1440\end{aligned}$

5 0

2 years ago

Read 2 more answers

The larger rectangle represents the phone smaller rating of operation specialist shaded area equation 2 inch border around the p

nirvana33 [79]

Answer: 160

Step-by-step explanation:

3 0

2 years ago

Your sister can get $30 per day, d, for selling clothes at the market. But she has to pay $60 at first for renting a stand. You

Alex

Answer:

6 days

Step-by-step explanation:

pay 60 = -60

Let d = the number of days

30d - 60 = sister

20d = me

Equation:

30d - 60 = 20d Move 30 to the other side

-30d -30d

-60 = 20d - 30d Combine liked terms

-60 = -10d

-10 -10 Divide

d = 6

5 0

3 years ago

For the functions f(x)=4x−3 and g(x)=3x2+4x, find (f∘g)(x) and (g∘f)(x).

barxatty [35]

Answer:

(16x + 21) and (16x - 6)

Step-by-step explanation:

f(g(x)) = f(6 + 4x)

Applying the f(x) function on (6 + 4x) gives

4(6 + 4x) - 3

Which equals 16x + 24 - 3

= 16x + 21

g(f(x)) = g(4x - 3)

Applying the g(x) function on (4x - 3) gives

6 + 4(4x - 3)

Which equals 6 + 16x - 12

= 16x - 6

7 0

3 years ago