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PIT_PIT [208]
3 years ago
15

Determine the relationship of AB and CD given the following points: A (2, -3), B (4,-6), C (7, 2), and D (5,

Mathematics
2 answers:
Maru [420]3 years ago
6 0
The answer is A) Parallel
iVinArrow [24]3 years ago
3 0

Answer: A. Parallel

Step-by-step explanation:

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Which number has the smallest value
tester [92]

Answer:

c would be the correct answer

Step-by-step explanation:

4 0
3 years ago
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I NEED HELP FASTTTTT
mezya [45]

Answer:

A, E

Step-by-step explanation:

You have to look for the ordered pairs where x (the first digit) doesn't repeat. that's a + e

6 0
3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
Question :
Aleks [24]

Answer:

9+r

Step-by-step explanation:

jessica rode 9 more miles so u would add it to the number of miles roger rode

7 0
4 years ago
The sum of two numbers is 22 and their difference is 12 what are the numbers
nlexa [21]

Answer:

The numbers are 17 and 5

Step-by-step explanation:

x + y = 22

x - y = 12

Add y to both sides of the equation

x = 12 + y

Substitute new value for x into first equation

12 + y + y = 22

Add the y's

12 + 2y = 22

Subtract 12 from both sides

2y = 10

y = 5

22 - 5 = 17

The numbers are 17 and 5

Hope this helps :)

8 0
3 years ago
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