All categories

2 years ago

Round your answer to the nearest hundredth.

Mathematics

1 answer:

Natali5045456 [20]2 years ago

5 0

Answer:

uh, I think it's 4.13

Step-by-step explanation:

5*sin(65)=4.13 now this seems a bit off but this was the only one that actually worked

You might be interested in

I WILL GIVE BRAINLIEST! Please answer these 5 questions correctly! (NO INCORRECT ANSWERS LINKS WILL BE REPORTED NO TROLL ANSWERS

BlackZzzverrR [31]

Answer:

1.) 4a + 55

2.) 88m + 24k - 55

4.) b and d

5.) b and d

6.) a

7.) 3x + x + 10

Step-by-step explanation:

Hope this helped :)

5 0

2 years ago

Write 6.75 as a mixed number.

KonstantinChe [14]

Answer:

Question 1 6 1/2

Step-by-step explanation:

Question 2 289/50

4 0

2 years ago

Read 2 more answers

I need help pleaseeeee No links

RUDIKE [14]

2 x 64 + 4 x 48 = 128 + 192 = 320

The pitchers can hold 320 ounces altogether.

pls mark me as brainliest!

7 0

2 years ago

Find the distance between the points ( – 9, – 4) and ( – 4,8).

Dmitriy789 [7]

Answer:

$Distance=13\ units$

Step-by-step explanation:

Distance between two points: Distance between two pints $(x_1,y_1)\ and\ (x_2,y_2)$ is given by

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between $(-9,-4)\ and\ (-4,8).$

$d=\sqrt{(-4-(-9))^2+(8-(-4))^2}\\\\d=\sqrt{(-4+9)^2+(8+4)^2}\\\\d=\sqrt{(5)^2+(12)^2}=\sqrt{25+144}\\\\d=\sqrt{169}\\\\d=13$

6 0

2 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

2 years ago