Question

F(x)=x² + 6x-11 Write the equation in vertex form.

Answer 1

Answer:

$f(x)=(x+3)^{2}-20$

Step-by-step explanation:

we have

$f(x)=x^{2}+6x-11$

To convert to vertex form complete the square

$f(x)=(x^{2}+6x+3^2)-11-3^2$

$f(x)=(x^{2}+6x+9)-20$

Rewrite as perfect squares

$f(x)=(x+3)^{2}-20$ ----> equation in vertex form

The vertex is the point (-3,-20) (is a minimum)