Corn is 2 can for $0.69, so each can of corn cost $0.345. How much does it cost for each one?

Over two summers, Ray saved $900 and $500. The polynomial 900x2 + 500x represents his savings at the beginning of the third year

Delicious77 [7]

C. is the correct answer

4 0

3 years ago

PLEASE HELP!!!!!!!!

dexar [7]

Bee Movie Script - Dialogue Transcript

According to all known laws

of aviation,

there is no way a bee

should be able to fly.

Its wings are too small to get

its fat little body off the ground.

The bee, of course, flies anyway

because bees don't care

what humans think is impossible.

Yellow, black. Yellow, black.

Ooh, black and yellow!

Let's shake it up a little.

Barry! Breakfast is ready!

Ooming!

Hang on a second.

Hello?

- Barry?

- Adam?

- Oan you believe this is happening?

- I can't. I'll pick you up.

Looking sharp.

Use the stairs. Your father

paid good money for those.

Sorry. I'm excited.

Here's the graduate.

We're very proud of you, son.

Step-by-step explanation:

5 0

3 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

5 0

3 years ago

If f(x)=x-3, which inequality can be used to find the domain of f(x)?

Scrat [10]

Given that,

$f(x) = \sqrt{x-3}$

To find,

The domain of f(x).

Solution,

We have, $f(x) = \sqrt{x-3}$

To find domain,

The term under the square root must be positive or null as follows :

$x-3\ge 0$

Adding 3 both sides

$x-3+3\ge 0+3\\\\x\ge 3$

So, the domain is x-3>0 .

3 0

3 years ago

Simplify the following expression.<br><br> 99 - 3[15 - (2 + 1)]

Vikki [24]

Answer:

63

Step-by-step explanation:

2+1= 3

15-3= 12

12 x 3 = 36

99 - 36

= 63

6 0

3 years ago

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