9514 1404 393
Answer:
3. m∠A < 80°
Step-by-step explanation:
The exterior angle NGS, marked as 80°, has a measure that is the sum of the measures of the remote interior angles: GAN, GNA.
If we assume that angle measures cannot be zero, then we must have ...
m∠A +m∠N = 80°
m∠A = 80° -m∠N
Since m∠N > 0, the measure of angle A must be less than 80°.
This conclusion matches choice 3.
(n-21)/2=4n is the equation
First, divide what is in the parentheses by 2
0.5n-10.5=4n
Then, multiply the whole equation by 2 so we have all whole numbers
n-21=8n
Move N so that it is with 8n
7n=-21
Divide 21 by 7
n=-3
Solution: The number (n) is equal to -3
Answer:
(a) The sample sizes are 6787.
(b) The sample sizes are 6666.
Step-by-step explanation:
(a)
The information provided is:
Confidence level = 98%
MOE = 0.02
n₁ = n₂ = n
Compute the sample sizes as follows:
Thus, the sample sizes are 6787.
(b)
Now it is provided that:
Compute the sample size as follows:
![n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%28z_%7B%5Calpha%2F2%7D%29%5E%7B2%7D%5Ctimes%20%5B%5Chat%20p_%7B1%7D%281-%5Chat%20p_%7B1%7D%29%2B%5Chat%20p_%7B2%7D%281-%5Chat%20p_%7B2%7D%29%5D%7D%7BMOE%5E%7B2%7D%7D)
![=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2.33%5E%7B2%7D%5Ctimes%20%5B0.45%281-0.45%29%2B0.58%281-0.58%29%5D%7D%7B0.02%5E%7B2%7D%7D%5C%5C%5C%5C%3D6665.331975%5C%5C%5C%5C%5Capprox%206666)
Thus, the sample sizes are 6666.
Answer:
The measure of the fourth angle = 137.1°
Step-by-step explanation:
Let x = the measure of the fourth angle
Sum of all 4 interior angles in a quadrilateral equal 360°
so
x + 23.5° + 99° + 100.4° = 360°
x + 222.9° = 360°
x = 360° - 222.9°
x = 137.1°
Tan(12) = 40/d
d = 40/tan(12)
d = 188.19m
