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Free_Kalibri [48]
2 years ago
15

Dave has a board that is

Mathematics
1 answer:
Naya [18.7K]2 years ago
4 0

Answer:

The answer is 1 3/8 (B)

Step-by-step explanation:

3 1/4 - 1 7/8 = 1 3/8

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Add. (5x - 2y + 7) + (3x + y - 8)
Schach [20]

Answer:

=8x-y-1

Step-by-step explanation:

So we have the expression:

(5x-2y+7)+(3x+y-8)

Combine like terms:

=(5x+3x)+(-2y+y)+(7-8)

Add:

=8x-y-1

And we're done!

3 0
3 years ago
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An operational definition is used to ____ a hypothetical construct.
Alona [7]
An operational definition can both define and measure the hypothetical construct. The hypothetical construct is also called psychological construct is an explanatory variable which cannot be directly observed. It is also a tool to understand someone’s behavior. For example measuring you friend happiness.
8 0
3 years ago
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How could you find an even better estimate of the square root of 2
vodomira [7]

Answer:

First of all you need to know the \sqrt {4} it's equal to 2 and

\sqrt {1} which is the number is between 1 and 2 and between that number there maybe the possibilities of above 0.5 or under 0.5

After that Figure out which one was bigger?  \sqrt {2} or \sqrt {3} ? The answer is \sqrt {3} and \sqrt {3} also near to \sqrt {4} so it should be above 0.5 .

So we know that \sqrt {2} is between 1 and 1.5.

Hopes that information was help you a lot

6 0
3 years ago
Whats 1+1 lol I need help
ryzh [129]

Answer:

Baby 1

Step-by-step explanation:

Mommy 1 and Daddy 1 have some fun, they had so much fun that they made baby 1

6 0
3 years ago
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A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
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