All categories

3 years ago

How do you solve -1x+20 is greater than -7+35

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

$\huge\fbox{Hello~there!}$

Let's solve this inequality!

$\rm{-x+20>-7+35$

What can we do to solve this inequality? Well, first of all, we can add -7 and 35:

$\rm{-x+20>28$

Now, move 20 to the right, using the opposite operation:

$\rm{-x>28-20$

Subtract:

$\rm{-x>8$

Divide both sides by -1 to isolate x:

$\rm{x$ (Answer)

_____________

<em>Additional comment</em>

When we divide both sides of an inequality by a negative number, we flip the inequality sign.

____________

I hope you find it helpful.

Feel free to ask if you have any questions.

$\bf{-MistySparkles^**^*$

You might be interested in

Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

3 0

3 years ago

Describe the locus in space.

yanalaym [24]

Answer: an endless cylinder with radius 4 mm and centerline

8 0

3 years ago

5 b.) Bill swims 2/3 of a lap in 7 minute.<br> What is his speed in laps per minute?

Arlecino [84]

Answer:

.095 laps per minute (if you need this answer as well 10.5 minutes per lap)

Step-by-step explanation:

(2/3)/7 =.095238 this is laps per min

7/(2/3)= 10.5 this is minutes per lap

I hope this is what you were looking for.

8 0

2 years ago

B. At the circus, three adult tickets and five child tickets cost $51, and five adult tickets

allsm [11]

Answer: x = $7, y = $6

Step-by-step explanation:

Let x be the cost of an adult ticket

Let y be the cost of a children's ticket

Translate these sentences to algebra:

At the circus, three adult tickets and five child tickets cost $51: 3x + 5y = 51

Five adult tickets and two child tickets cost $47: 5x + 2y = 47

Now we have two equations. Let's use substitution to solve.

3x + 5y = 51

3x = 51 - 5y

.: x = 17 - 5y/3

Now substitute this value of x into the second equation to find the numerical value of y:

5(17 - 5y/3) + 2y = 47

85 - 25y/3 + 2y = 47

-19y/3 = -38

-19y = -114

.: y = 6

Now find x:

x = 17 - 5y/3

x = 17 - 10

.: x = 7

So an adult ticket costs $7, and a child ticket costs $6 :)

3 0

2 years ago

7. A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the

svp [43]

Answer: 475.59 meters .

Step-by-step explanation:

The correct equation is the following:

$y =-0 .02x^2 +9.5x + 5.6$

For this exercise you need to use the Quadratic formula:

$x = \frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case you can identify that the values of "a", "b" and "c" are:

$a=-0.02\\\\b=9.5\\\\c=5.6$

Now you must substitute these values into the Quadratic formula and then evaluate. You get:

$x=\frac{-9.5\±\sqrt{(9.5)^2-4(-0.02)(5.6)}}{2(-0.02)}\\\\x_1=475.588\\x_2=-0.588$

Choose the positive one and round it to the nearest hundreth:

$x_1\approx 475.59$

4 0

3 years ago