Answer:
4th term is -37.
Step-by-step explanation:
a2 = 2a1 - 3 = 2(-2) - 3 = -7
a3 = 2(-7) - 3 = -17
a4 = 2(-17) - 3 = -37.
To solve the exponential growth application question we proceed as follows;
suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.
Note theta the population is in millions;
The exponential formula is given by:
f(t)=ae^(kt)
where;
f(t) =current value
a=initial value
k=constant of proportionality
t=time
substituting the values we have in our formula we get:
132=127e^(7k)
132/127=e^(7k)
introducing the natural logs we get:
ln (132/127)=7k
k=[ln(132/127)]/7
k=0.0055
Thus our formula will be:
f(t)=127e^(0.0055t)
The population in 2008 will be:
f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922
Thus the population in 2008 is appropriately 138 million.
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10% of 10% is 0.01 then 1% of 1% is also 0.01
the same number of the same number is also 0.01 at this point:
25% of 25% is 0.01.
Rewriting input as fractions if necessary:
7/1, 343/1
For the denominators (1, 1) the least common multiple (LCM<span>) is </span>1.
Therefore, the least common denominator (LCD<span>) is </span>1.
<span>Rewriting the original inputs as equivalent fractions with the </span>LCD:
<span>7/1, 343/1</span>
Move it two times to the right