Question

Of 120 hotel rooms rented one night, some were suites rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals for this night was $10,890, how many suites were rented?
A) 23
B) 35
C) 54
D) 94
E) 99

Answer 1

Answer: A) 23

Step-by-step explanation:

Let x represent the number of suites that were rented.

Let y represent the number of double rooms that were rented.

The total number of rooms that were rented is 120. It means that

x + y = 120

some were suites rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals for this night was $10,890, it means that

115x + 85y = 10890 - - - - - - - - -1

Substituting x = 120 - y into equation 1, it becomes

115(120 - y) + 85y = 10890

13800 - 115y + 85y = 10890

- 115y + 85y = 10890 - 13800

- 30y = - 2910

y = - 2910/-30

y = 97

x = 120 - y = 120 - 97

x = 23