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Nikolay [14]
2 years ago
6

Fashoo G-looks brosay

Mathematics
1 answer:
Elodia [21]2 years ago
8 0

Answer:

what are you talkin bout fam? you speakin gibberish rn

Step-by-step explanation:

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In the graphic below,
sukhopar [10]

The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:

\begin{gathered} \angle d=180-\angle a \\ \angle b+\angle c=180-\angle a \end{gathered}

Then we can conclude that:

\angle d=\angle b+\angle c

Therefore the statement is true, the exterior angle is equal to the sum of its remote interior angles.

Let's use an example:

On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:

x=75+45=120

The sum of the remote interior angles is equal to the external angle.

6 0
1 year ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
SIMPLE CORDINATE PLOTTING! BRAINLIEST, 5 STAR, AND A LIKE ON UR ANSWER. SHOW SOME WORK.
Damm [24]

Answer:

A

Step-by-step explanation:

( 2, -5 )

( -2, -5)

Hope this helps dude

7 0
3 years ago
Read 2 more answers
Jordan is a student who hates to be called on in class. His teacher randomly calls on students and Jordan knows that on any give
Anika [276]

Answer:

0.1 for each case

Step-by-step explanation:

Because Jordan's teacher randomly calls on students and Jordan has 10% chance of being called on any given day, the probability that on the first day Jordan is called on is 0.1 Besides, the probability remains constant on any given day, so, the probability  that on the 2nd day Jordan is called on is 0.1 and for the 5th day is the same 0.1 Probability is always a number between 0 and 1.

7 0
3 years ago
I WILL GIVE BRAINLEST IF YOU ANSWER BOTH WITH EXPLANATION please dont let me fail :(
Lapatulllka [165]
I see grey but if that’s black okay.
2/5

You had a 2/5 chance
He had a 1/4 chance
8 0
3 years ago
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