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Andrew [12]
3 years ago
8

Which sequence of transformations will map figure H onto figure H′?Two congruent hexagons are shown on a coordinate plane; hexag

on H quadrant one with vertices at 2 comma 2, 2 comma 6, 6 comma 7, 8 comma 6, 8 comma 2, and 6 comma 1; hexagon H prime with vertices at 2 comma negative 8, 2 comma negative 4, 4 comma negative 3, 8 comma negative 4, 8 comma negative 8, and 4 comma negative 9. Rotation of 180° about the origin, translation of (x + 10, y − 2), and reflection across x = −6 Rotation of 180° about the origin, translation of (x + 10, y − 2), and reflection across y = −6 Rotation of 180° about the origin, translation of (x − 10, y + 2), and reflection across y = −6 Rotation of 180° about the origin, translation of (x − 10, y + 2), and reflection across x = −6
Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

Rotation of 180° about the origin, translation of (x + 10, y − 2), and reflection across y = −6

Step-by-step explanation:

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(x-2)e2/3=49<br><img src="https://tex.z-dn.net/?f=%28x%20-%202%29%20%5E%7B2%20%5Cdiv%203%7D%20%20%3D%2049%20" id="TexFormula1" t
fredd [130]

\bf (x-2)^{2\div 3}=49\implies (x-2)^{\frac{2}{3}}=7^2\implies \stackrel{\textit{raising both sides by }\frac{3}{2}}{\left( (x-2)^{\frac{2}{3}} \right)^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}} \\\\\\ (x-2)^{\frac{2}{3}\cdot \frac{3}{2}}=7^3\implies (x-2)^1=7^3\implies x=7^3+2\implies x=345

4 0
3 years ago
Which of the following expressions is a polynomial?
Cloud [144]
Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms


by 1. we eliinate 2nd one

by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder

thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9


last one is answer
5 0
3 years ago
Read 2 more answers
A researcher selects all of the possible samples with n = 8 scores from a population and computes the mean, dividing by n, for e
Nadusha1986 [10]

Answer:

By the Central Limit Theorem, the average value for all of the sample means is 14.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

If the population mean is μ = 14, then what is the average value for all of the sample means?

By the Central Limit Theorem, the average value for all of the sample means is 14.

3 0
3 years ago
Eva incorrectly classifies the quotient -(-81/-9) as positive.
NISA [10]
The answer is negative because, ( -81/-9) =(+9). -(+9) = -9. Maybe for got the - sign before the equation
6 0
3 years ago
4/5 + r=-3<br><br> What is the answer to this equation?
Zolol [24]

Answer:

r= -19/5

Step-by-step explanation:

6 0
3 years ago
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