<span>I have been a high school/jr high math teacher for the past 13 years. I am happy to explain how to proceed with this problem.
A square is a figure where ALL sides are exactly the same. The find the area of the square you would multiply one side times another side. You would be multiplying a number times itself. So if you already have the area, you would take the square root to find your answer. When you do, you end up with 21.21 square inches rounded to the nearest hundredth.</span>
Answer:
x=0
Step-by-step explanation:
3+5(0)=3
Answer:
4. AB=4
Step-by-step explanation:
Transitive property is like substitution, or that's how I like to think of it. Since we have 2 common variables and 2 equations, we can "link them together". Replacing x with 4, you get AB=4.
Seca(1-sina)(seca+tana)=1
Left hand side
=(1-sina) (seca +tana) / cosa
=seca +tana - sinaseca - sinatan / cosa
=seca + tana -tana -(sin^2a/cosa) / cosa
=(1/cosa - sin^2a/cosa) / cosa
= (1-sin^2a / cosa) / cosa
= (1-sin^2a)/ (cos^2a)
=1 (verified)
Answer:
We do not have enough evidence to accept H₀
Step-by-step explanation:
Normal Distribution
size sample = n = 64 (very small sample for evaluating population of 5 years
Standard deviation 4,8
1.- Test hypothesis
H₀ null hypothesis ⇒ μ₀ = 14 and
Hₐ alternative hypothesis ⇒ μ₀ ≠ 14
2.- z(c) we assume α = 0,05 as we are dealing with a two test tail we should consider α/2 = 0.025.
From z table we the z(c) value
z(c) = 1.96 and of course by symmetry z(c) = -1.96
3.- We proceed to compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n) ] ⇒ z(s) = - (1.5)*√64/4.8
z(s) = - 2.5
We compare z(s) and z(c)
z(s) < z(c) -2.5 < -1.96 meaning z(s) is in the rejection zone
we reject H₀ .
From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀
