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Mila [183]
2 years ago
13

joe has a handful of dimes and quarters that values to $5.30. He has one fewer than twice as many dimes than quarters. How many

of each coin does he have?
Mathematics
1 answer:
OlgaM077 [116]2 years ago
5 0

Answer:

12 quarters 23 dimes

Step-by-step explanation:

x(0.25)+(2x-1)(0.10)=5.30

0.25x+0.2x-0.10=5.30

0.45x=5.40

x=12

12 quarters

12(2)=24-1=23 dimes

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Answer:

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Step-by-step explanation:

TanA = -√15

.we are to find tan(A-π/4).

In trigonometry

Tan(A-B) = TanA - TanB/1+ tanAtanB

Hence:

tan(A-π/4) = TanA - Tanπ/4/1+ tanAtanπ/4

Substitute tan A value into the formula

tan(A-π/4) = -√15-tanπ/4 / 1+(-√15)(tanπ/4

tan(A-π/4) = -√15-1/1-√15

Rationalize

-√15-1/1-√15 × 1+√15/1+√15

= -√15-√225-1-√15/(1-√225)

= -2√15-15-1/1-15

= -2√15 -16/(-14)

= -2(√15+8)/-14

= √15 + 8/7

Hence the required value is ( √15 + 8)/7

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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