Question

Mr Lim gave $3600 to his wife and two children altogether. His wife received $500 more than his son. His son received twice as much as his daughter. How much did Mr Lim's wife receive?​

Answer 1

The amount of money Mr Liam's wife received is $2140

How much did Mr Lim's wife receive?​

The total money received by the three people can be represented with this equation : x + y + z = $3600

Where:

• x = amount Mr Lim's wife received = $500 + 2z
• y = amount the son received = 2z
• z  = amount the daughter received

The above equation can be rewritten as

$500 + 2z + 2z + z = $3600

In order to determine the value of z, take the following steps:

Combine similar terms

2z + 2z + z = $3600 + $500

Add similar terms

5z = $4100

Divide both sides by 5

z = $820

Mrs Liam's wife received : ($820 x 2) + $500 = $2140

To learn more about division, please check: brainly.com/question/13281206

Answer 2

Mr Lim's wife received the sum of $3600

Calculation of total sum received.

The total amount given out by Mr Lim = $3600

The total amount received by his wife = 500 + X

(where X is the amount received by the son)

But X is = 2d

where d is the amount received by the daughter.

therefore to calculate for x and d to find the amount received by Mr Lim's wife.

3600= 500+X

X = 3600 - 500

X = 3100

But X = 2d

substitute for x

3100 = 2d

d =3100/2

d= 1550

Therefore the amount received by Mr Lim's wife is =

500 +. 3100

= $3600

Learn more about addition here:

brainly.com/question/874745