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kogti [31]
3 years ago
12

Amy measured a house and made a scale drawing. The scale of the drawing was 5 millimeters : 2 meters. In the drawing, the dining

room is 20 millimeters long. What is the length of the actual dining room?
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer: Amy measured a house and made a scale drawing. The scale of the drawing was 5 millimeters : 2 meters. In the drawing, the dining room is 20 millimeters long. What is the length of the actual dining room?

Step-by-step explanation:

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BlackZzzverrR [31]

Answer: hello your question is poorly written below is the complete question

Find the angle between and if ⋅=3√2‖‖⋅‖‖.

(Use symbolic notation and fractions where needed. Give your answer in terms of . )

answer :

∅ = π / 6

Step-by-step explanation:

V .W = \frac{\sqrt{3} }{2}  || V ||. ||W||

Hence

∅ = cos^-1 ( \frac{\frac{\sqrt{3} }{2}  || V ||. ||W||}{||V||.||W||}

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∴ ∅ = π / 6

4 0
3 years ago
How many sixths are in 4
pochemuha
If you would like to know how many sixths are in 4, you can calculate this using the following steps:

n ... the number of sixths
n * 1/6 = 4
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3 0
3 years ago
The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma
kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, H_0 : \mu = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, H_1 : \mu > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

           T.S. = \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 1.20 A

                 s = sample standard deviation = 0.42 A

                 n = sample size = 11 motors

So, Test statistics = \frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } } ~ t_1_0

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At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0
4 years ago
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Answer: 24?

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Answer:

The bbn vxcndzx Decide which item would best check the reliability of each statement.

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Step-by-step explanation:

3 0
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