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Stells [14]
3 years ago
11

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

=
Mathematics
1 answer:
Lynna [10]3 years ago
4 0

ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

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