The probability would be 81/32,768
<h3>Dihybrid crossing</h3>
Both parents are heterozygous at both loci, meaning that their genotype is HhWw.
Crossing two HhWw:
HhWw x HhWw
Offspring;
H_W_ - smooth toes, sticky earwax = 9/16
H_ww - smooth toes, brittle earwax = 3/16
hhW_ - hairy toes, sticky earwax = 3/16
hhww - hairy toes, brittle earwax = 1/16
Probability of a boy = 1/2
Probability of a girl = 1/2
Probability of having hairy toe, brittle earwax boy = 1/16 x 1/2
= 1/32
Probability of smooth toe, sticky earwax girl = 9/16 x 1/2
= 9/32
Probability of one hairy-toed, brittle ear-waxed boy and two smooth-toed, sticky ear-waxed girls = 1/32 x 9/32 x 9/32
= 81/32,768
More on dihybrid crosses can be found here: brainly.com/question/1185199
