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Anit [1.1K]
2 years ago
8

What method of choice do you use to solve 8x+5y=-13 and 3x+4y=10

Mathematics
1 answer:
nordsb [41]2 years ago
4 0

Answer:

y = 17, x = -12.25

Step-by-step explanation:

Elimination method is preferred.

Refer to attachment.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

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Which is equivalent
arlik [135]

Answer:

D  8√(10) ^3x

Step-by-step explanation:

We have

sqrt(10) ^ (3/4x)

We can rewrite the sqrt as ^1/2

10 ^ (1/2) ^ (3/4x)

We know that a^b^c = a^(b*c)

10 ^(1/2 *3/4x)

10 ^(3/8 x)

The numerator is the power

The denominator is the root

8√(10) ^3x

8 0
3 years ago
Can u guys PLEASE explain the difference between 2 x 10 to the power of 4 and 2 to the power of 4
Alexxx [7]

Answer:

see explanation

Step-by-step explanation:

2 × 10^{4}

= 2 × 10 × 10 × 10 × 10

= 2 × 100 × 100

= 200 × 100

= 20000

And

2^{4}

= 2 × 2 × 2 × 2

= 4 × 4

= 16

7 0
4 years ago
Solve for g<br> –4g + 10 = –10 + g
sergey [27]

Answer: g=4

Step-by-step explanation:

6 0
3 years ago
Select the correct answer. Find the solution(s) for x in the equation below.<br> x2-9x+20=0
trasher [3.6K]

Step-by-step explanation:

Given

x² - 9x + 20 = 0

x² - ( 4 + 5) x + 20 = 0

x² - 4x - 5x + 20 = 0

x ( x - 4 ) - 5 (x - 4 ) = 0

(x - 4 ) ( x - 5 ) = 0

Either

x - 4 =0

x = 4

or

x - 5 =0

x = 5

x = 4 and 5

Hope it will help :)

.)

8 0
3 years ago
Read 2 more answers
A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i
yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

T - Ts = (T_0 - Ts)e^k^t

We'll solve for k

35 - 100 = (20 - 100)e^9^k

-65 = (-80)e^9^k

Divide both sides by -5

13 = (16)e^9^k

9k = ln (\frac{13}{16})

k = \frac{1}{9} ln (\frac{13}{16})

k = -0.02307104053

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T - Ts = (T_0 - Ts)e^k^t

T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100= -52.8125

T = 100 - 52.8125

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0
4 years ago
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