7/438.... just solve it like thus.....EVERY FRACTION IS A DIVITION PROBLEM
Answer:
C
Step-by-step explanation:
because 30÷6 is 5 and that is what should be placed
Answer:
law of cosines
c^2=(5)^2+(12)^2-2(5)(12)cos72
Answer:
The answer is 4
Step-by-step explanation:
16-4(3)
16-12
4
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
