In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and
1 answer:
Answer:
The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively
The possible pairs of the coordinates of the point B are found as follows;
1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above
2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the perpendicular intersection of the two newly constructed lines here
Step-by-step explanation:
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For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following points through which the line passes:
We find the slope of the line:
Thus, the equation of the line is of the form:
We substitute one of the points and find b:
Finally, the equation is:
Answer: