In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and
1 answer:
Answer:
The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively
The possible pairs of the coordinates of the point B are found as follows;
1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above
2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the perpendicular intersection of the two newly constructed lines here
Step-by-step explanation:
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To solve this, we have to find the volume of the cylinder first. The formula to be used is 
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
x 10cmV= (3.14)(
) x 10cmV= (
) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.