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-Dominant- [34]
2 years ago
8

Which is the correct classification and decimal expansion of StartFraction 5 Over 8 EndFraction?

Mathematics
1 answer:
dimulka [17.4K]2 years ago
8 0

Answer:

Its 0.025 I think

Step-by-step explanation:

You might be interested in
what is the scale factor of triangle UVW to triangle XYZ where uvw has side Lengths 3,4,2, and XYZ has lengths 14,28,21
alekssr [168]

Answer: 7

Step-by-step explanation:

Given:  Triangle UVW map to triangle XYZ where Triangle UVWhas side Lengths 3,4,2, and triangle XYZ has lengths 14,28,21.

We know that the scale factor between two similar figures is the the ratio of the corresponding side of image to the original figure.

Let k be the scale factor.

Then,

k=\frac{21}{3}=\frac{14}{2}=\frac{28}{4}=7\\\\\Rightarrow\ k=7

Hence, the scale factor = 7

8 0
3 years ago
Find the quotient of 3/4 divided by 2/3
MrMuchimi

Answer:

1.125

Step-by-step explanation:

6 0
2 years ago
Is 10.846 an integer ​
yulyashka [42]

Hello!

An integer is defined as a number which is not a fraction or irrational. It should be able to be written out as just a number, without a decimal point or additional fraction. (It can have a negative sign) For example, a few integers would be 2, 5, -8, and 9109, while some non-integers would be 3.1, 3 3/2, and 5i.

In this case, 10.846 is not an integer, as it has a decimal.

Hope this helps!

3 0
3 years ago
3.14 times 16 divided by 3
AleksAgata [21]

Answer:

The answer is 16.746667

Step-by-step explanation:

1) Simplify 3.14 × 16 to 50.24.

50.24 \div 3

2) Simplify 50.24 ÷ 3 to 16.746667.

16.746667

<u>Therefor</u><u>. </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>16.746667.</u>

5 0
2 years ago
Glen is planting square flower gardens surrounding a triangular fishpond as shown. If the sides of the triangular fishpond are 5
weqwewe [10]

Answer:

h=\sqrt{106} \approx 10.3 feet

Step-by-step explanation:

We will use the Pythagorean Theorem to solve this. Which states that:

One Length^2 + Another Length^2 = Hypotenuse^2

We can take one length as 5 ft and another length as 9 ft and we call the hypotenuse "h", so we have:

5^2+9^2=h^2

Now, let us solve for "h":

5^2+9^2=h^2\\25 + 81 = h^2\\106=h^2\\h=\sqrt{106} \approx 10.3

The pond's hypotenuse is about 10.3 feet

3 0
3 years ago
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