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AURORKA [14]
3 years ago
10

Theta is an angle in standard position with the terminal side passing through (-7,8) find the exact value of tantheta

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0
<span> The angle which is in the standard position has the initial side along the positive x-axis. According to the picture, since tan theta is equal to tan beta, tan theta is  8/7 .    8/7 =1.14285714</span>

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Blababa [14]
I would guess A OR D

6 0
4 years ago
What is a theoretical and Experimental Probability?
aniked [119]

Answer:

See below...

Step-by-step explanation:

Theoretical probability is the probability that something should happen based on the beginning conditions.  Such as having a jar of 30 marbles with 5 being blue.  The probability of pulling out a blue marble when selecting 1 marble is

5/30, or 1/6.  Theoretically you should pull one blue marble out every 6 times you pull a marble out.  

This isn't guaranteed to happen though, that's where experimental probability comes form.

Experimental probability is the number of desired outcomes achieved, divided by the total number of outcomes.  This is based on what actually happened.  Say you selected a marble, and put it back 10 times, recording the color each time and you got 2 blue marbles.  Your experimental probability is

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8 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
Mashutka [201]

Here is the full question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

Equation:

y=-16x^2+153x+98

Answer:

10.2 seconds

Step-by-step explanation:

Given equation :

y=-16x^2+153x+98 shown the expression of a quadratic equation

Let y =0

∴

0 = -16x^2+153x+98

where;

a=-16\\b=153\\c=98

Using the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

replacing it with our values; we have:

x=\frac{-153\±\sqrt{153^2-4(-16)(98)}}{2(-16)}

x=\frac{-153\ + \sqrt{153^2-4(-16)(98)}}{2(-16)}    OR     x=\frac{-153\ - \sqrt{153^2-4(-16)(98)}}{2(-16)}

x_1=10.17   OR     x_2=-0.60

Hence, we go by the positive value since,  is the time that the rocket will hit the ground.

x= 10.17

x = ≅ 10.2 seconds

Therefore, the rocket will hit the ground,  to the nearest 100th of second.  = 10.2 seconds

6 0
4 years ago
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ycow [4]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Use the diagram in the photo to answer the questions that follow.
AURORKA [14]

Answer:

Step-by-step explanation:

1. y =25x

2. answer : 250

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6 0
3 years ago
Read 2 more answers
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