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8_murik_8 [283]
2 years ago
14

28 students travel on a field trip. They bring a van that can seat 12 students. Elena and Kiran's teacher asks parents to drive

cars that seat 3 children each to transport the rest of the students.
Elena wonders if she should use the inequality
12+3>28
12
+
3
n
>
28
or
12+3≥28
12
+
3
n
≥
28
to figure out how many cars are needed. Kiran doesn't think it matters in this case. Solve the inequality to explain why Kiran is correct. (use / to represent fractional quantities and a space between whole numbers and the fraction. Example
112
1
1
2
type as 1 1/2)


n
Mathematics
2 answers:
zubka84 [21]2 years ago
6 0

Answer: Yes, you can use this inequality to find the numbers of cars required.

Step-by-step explanation:

12  + 3n > 28     where n = the number of cars required

3n > 28 -12

3n > 16

n > 5 1/3

Greater than 5 1/3 gives 6 cars.

Jlenok [28]2 years ago
6 0

Answer:

See below.

Step-by-step explanation:

12 + 3n ≥ 28

3n ≥ 16

n ≥ 5 1/3

The number of cars must be equal to or greater than 5 1/3.

Since there is no 1/3 of car, that means there must be 6 cars.

Whether the inequality is 12 + 3n > 28 with a solution of more than 5 1/5 or the inequality is 12 + 3n ≥ 28 with a solution of 5 1/3 or more, the answer is the same because the minimum number of cars that will be enough is 6.

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A motorboat takes 3 hours to travel 108 km going upstream. The return trip takes 2 hours going downstream. What is the rate of t
PtichkaEL [24]
Recall your d = rt, distance = rate * time.

let's say the boat has a still water rate of "b", and the current has a a rate of "c", ok.... when the boat is going upstream, is not really going "b" fast, is going  slower at "b - c", due to the current going in the opposite direction.

when the boat is coming downstream, is not going "b" fast either, is going faster, is going "b + c", due to the current adding speed to it.

we know the trip up was 108 kms, thus the return trip is also 108 kms.

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
Upstream&108&b-c&3\\
Downstream&108&b+c&2
\end{array}
\\\\\\
\begin{cases}
108=3(b-c)\implies \cfrac{108}{3}=b-c\implies 36+c=\boxed{b}\\\\
108=2(b+c)\\
--------------------\\
108=2\left(\boxed{36+c} +c \right)
\end{cases}
\\\\\\
\cfrac{108}{2}=36+2c\implies 54=36-2c\implies \cfrac{54-36}{2}=c

and surely you know how much that is.

what's the boat's speed? well, 36 + c = b.
8 0
3 years ago
What is the percent as a fraction in lowest terms
Gwar [14]
1/100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 0000000000000000000000000000 etc.
4 0
3 years ago
The slope of the line below is -2. Use the coordinates of the labeled point to
Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

y(x)=mx+b\\\\y(x)=-2x+b

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

y_0=-2x_0+b

Then, we can calculate b as:

y_0=-2x_0+b\\\\b=y_0+2x_0

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)

6 0
3 years ago
Is (3,-1) a solution of this system: y=2-x 3-2y=2x
I am Lyosha [343]
Plug in (3,-1) into equations to see:
-1=2-3
-1=-1 CHECK

3-2(-1)=2(3)
3+2=6
5=6 NO

This is not a solution.
8 0
3 years ago
Solve for X. The Triangles in each pair are similar
Klio2033 [76]

Answer:

x = 7

Step-by-step explanation:

In this question, we need to find what the value of x is.

To do so, we need to find the value of the change of the triangle, since the triangles are basically the same

We know to get from 18 to 27, we would need to multiply 18 by 1.5.

This means that the triangle "BCD" is increasing from 1.5 to get "JKL"

With this knowledge, we also know that side CB, 10, needs to increase by 1.5

When you multiply 10 by 1.5, you get 15.

The triangle side "JK" is the same side as "CB", so we need to find what makes the value of 15 for the "JK" side.

To do this, solve 3x-6 for 15.

3x - 6 = 15

Add 6 to both sides.

3x = 21

Divide both sides by 3

x = 7

The x-variable would be 7.

5 0
3 years ago
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