2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
I’m pretty sure that it’s b
Answer:
quarts
12 days
Step-by-step explanation:
Given that:
Amount of water leaked in 4 days = 3 quarts
To find:
Number of quarts leaked in 1 week?
Number of days taken for the leakage of 9 quarts of water?
Solution:
We can simply use unitary method or the ratio to find the answers of the questions asked in the statement.
As per question statement:
Amount of water leaked in 4 days = 3 quarts
Dividing by 4 on both sides:
Amount of water leaked in 1 day =
quarts
Multiplying by 7 on both sides:
Amount of water leaked in 7 days =
quarts
Number of days taken for the leakage of 3 quarts = 4 days
Multiplying by 3 on both sides:
Number of days taken for the leakage of 3
3 = 9 quarts = 4
3 = <em>12 days</em>
Answer:
Just tried this on a calculator
)) i think its 7/2!
Step-by-step explanation:
<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>