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2 years ago

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What is the coefficient in this expression?5 minus 4.7 minus 2 x + StartFraction 5 over 8 EndFractionNegative 4.7Negative 2Start

Fraction 5 over 8 EndFraction5

1 answer:

WITCHER [35]2 years ago

4 0

Answer:

-2

Step-by-step explanation:

i did the test

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ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

2 years ago

Question 7 a desk is on sale for 35% off. the sale price is $559 . what is the regular price?

marshall27 [118]

559 x 0.65 = 363.35 $

8 0

2 years ago

the cost of using a card is 35 cents per call plus 25 cents per minute. A recent call cost cost $12.35. write and solve the equa

LUCKY_DIMON [66]

If the call cost 35 cents to use the card that leaves $12 that was from minutes. There is 4 quarters in a dollar, 12x4 is 48.

VERIFY:
$1=4
$2=8
$3=12
$4=16
$5=20
$6=24
$7=28
$8=32
$9=36
$10=40
$11=44
$12=48

4 0

3 years ago

What’s the area of the triangle??

viktelen [127]

Note that one side is 20 ft, and the other is 16.

This means that the side that is part of the triangle is 4 ft.

The measurement is still the same for the triangle's height.

Find the area of the rectangle:
24 x 16 = 384
Find the area of the triangle:
4 x 24 = 96

Add the two numbers together:

384 + 96 = 480

You're answer is (C)

hope this helps

5 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago