He has $.50 left
1/2 on baseball cards = $2.00
1/4 on a drink = $1.00
1/8 on bible gum = $.50
Which adds up to $3.50 so therefore he has 50 cents left
4.00 - 3.50 = .50
2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)
2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)
2b(b - a) + 2a(b + a)
= ------------------------------------
(b+a)(b+a)(b-a)
2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
(b+a)(b+a)(b-a)
2b^2 + 2a^2
= ------------------------
(b+a)(b+a)(b-a)
2(b^2 + a^2)
= ------------------------
(b+a)^2 (b-a)
Answer:
Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)
Your correct it’s the first one
Write the coeeficientes of the polynomial in order:
| 1 - 5 6 - 30
|
|
|
------------------------
After some trials you probe with 5
| 1 - 5 6 - 30
|
|
5 | 5 0 30
-----------------------------
1 0 6 0 <---- residue
Given that the residue is 0, 5 is a root.
The quotient is x^2 + 6 = 0, which does not have a real root.
Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.
Answer:
She did not represent the two original factors correctly on the headers.
Step-by-step explanation:
Adi algebra tiles representation is shown in the figure attached.
She made a mistake when she represented -2x-1 with two negative tiles in the top header
, so, the representation in the header is not correct.
