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3 years ago

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Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

3 0

$2\cdot 10^{3x}=26\\10^{3x}=13\\\log 10^{3x}= \log 13\\3x\log 10= \log 13\\3x= \log 13\\\\$

$x=\frac{\log 13}{3}$

lmk if you have questions

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When you subtract a number, you get the same results as when you add the opposite number. Why?

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Answer:

Step-by-step explanation:

Well, the opposite of a number is the same number with the opposite sign. For example, the opposite of -1 is 1.

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Find Lowest common factor of following questions . 56, 42, 28

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Answer:

$\boxed{\textsf{ The LCM of 56 , 42 , 28 is \textbf{ 168}.}}$

Step-by-step explanation:

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Related Information :- 

• HCF :-

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3 years ago

Identity the composite number represented by the prime factorization below

Korolek [52]

Answer:look below

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3 years ago

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2 years ago

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-3x^{2}-21x-54 what are the zeros? (Solutions)

Irina-Kira [14]

The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

x^2+7x+18
a=1
b=7
c=18

x= $\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}$
x= $\frac{-7+/- \sqrt{49-72} }{2}$
x= $\frac{-7+/- \sqrt{-23} }{2}$
i=√-1
x= $\frac{-7+/- i\sqrt{23} }{2}$

the zerose would be
x= $\frac{-7+ i\sqrt{23} }{2}$ or $\frac{-7- i\sqrt{23} }{2}$

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2 years ago