So idk how i'm going to show this w/out graph paper, so bear with me on the answer.
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Just count the spaces between the points. Since it's a parallelogram, that means that length of CD= length of AB, and length of DB= length of BC, so using either length(s) is fine.
By counting we know that the length for CD is 14.
Then count the distance between D and A (or C and B). this is including the x-distance, not just the y, so we end up with 27. Then 27×14=378units²
Idk if I did this right, but I tried my best :D
You have to use let statements:
Let x = the number of dimes
Let x+6 = the number of nickles
We know that nickles are represented as $0.05 and dimes $0.10...
Together they make $2.25 right? So you have to add them.
0.05(x+6) + 0.10(x) = 2.25 => This is the equation the problem is asking for.
If they ask you how many nickels and dimes does John have in this pocket, then you have to solve for x, like this:
0.05x + 0.3 + 0.10x = 2.25 In this step you apply the ditributive property.
0.15x + 0.3 = 2.25 In this step you combine like terms
0.15x = 2.25 - 0.3 In this step you moved to +0.3 to the other side, but remember to switch the sign!
0.15x = 1.95 In this step you subtract 2.25 and 0.3
x = (1.95) / (0.15) In this step you divide 0.15 in the right because in the left side of the equals sign it was multiplying. You get x by itslef.
x = 13 Latly, you divide and you get 13 as an answer
Now that the value of x is 13. You plug this number into the let statements.
We had:
x and x+6 which would be
x = 13
x+6 = 13+6 = 19
Which means that John has 13 dimes and 19 nickels in his pocket.
Answer:
5 feet
Step-by-step explanation:
Since you know that the ratio is 1:250, you set up a second ratio that looks like this:
x:1,250, where x is the unknown height of the model.
Then divide 1,250 by 250 bc the real building is 250 times larger than the model. 1,250/250=5, so the model should be 5 feet tall
Answer:
8%
Step-by-step explanation:
12/250=0.08
0.08=8%
0+1+9, 0+2+8, 0+3+7, 0+4+6, 0+5+5 gives 27 ways including permutations.
1+1+8, 1+2+7, 1+3+6, 1+4+5 gives 21 ways.
2+2+6, 2+3+5, 2+4+4 gives 12 ways
3+3+4 gives 3 ways
With permutations this gives 27+21+12+3=63 ways.