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Aleksandr-060686 [28]

2 years ago

13

A spinner is divided into 15 identical sectors and labeled 1 through 15.

1 answer:

katovenus [111]2 years ago

3 0

Answer:

spin it 35 times

Step-by-step explanation:

there are 3 multiples of 4 under 15 (4,8,12) so the chances of a 4 will be 3/15 or 1/5 to find the chances of 7 times just multiply by 7 so the finale answer is 1/35

P.S. please give brainliest

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Lily has $2. 75 in her pocket, consisting of dimes and quarters. If there are 17 coins in all, how many of each does she have?.

Nikitich [7]

Answer:

Lily has 7 Quarters and 10 Dimes

Step-by-step explanation:

Let's use pennies instead of $.

Let <u>D</u> and <u>Q</u> stand for the numbers of Dimes and Quarters, respectively.

We are told that there are 17 coins total:

<u> D + Q = 17</u>

We also learn that they amount to 275 (pennies). We can write that as:

<u>10D + 25Q = 275</u> [Each D is worth 10 pennies, etc.]

We have two equations and two unknowns. We can rearrange one equation to find the value of either of the unknowns, and then use that it the second equation.

I'll rearrange the first:

D + Q = 17

<u> D = 17 - Q</u>

Now use this value of D in the second equation:

10D + 25Q = 275

10(17-Q) + 25Q = 275

170 - 10Q + 25 Q = 275

15Q = 105

<u>Q = 7 : 7 Quarters.</u>

<u></u>

Since D + Q = 17:

D + 7 = 17

<u>D = 10 Dimes</u>

==========================================

Let's check these results:

Q = 7 Quarters

D = 10 Dimes

1. Is this 17 coins in total? (7+10 = 17) <u>YES</u>

2. Does this add to $2.75? (10*10) + (7*25) = 275 cents?

(100 + 176) = 275 (cents) <u>YES</u>

============================

Lily has 7 Quarters and 10 Dimes

8 0

3 years ago

PLEASE HELP !!!!!!!!!!!!!!!!!!! I REWARD BRAINLIEST

Readme [11.4K]

Answer:

................

x=23°

x=14°

6 0

3 years ago

Read 2 more answers

Use the procedures developed to find the general solution of the differential equation. (Let x be the independent variable.)

makkiz [27]

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

$(a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)$ is a differential equation.

If $Q(x) \neq 0$

It is non homogeneous then,

The general solution = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution = complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

$(2D^3+15D^2+24D+11)y=0$

Auxiliary equation,

$2m^3+15m^2+24m +11 = 0$

-1 | 2 15 24 11

<u> | 0 -2 - 13 -11 </u>

2 13 11 0

∴ $2m^2+13m+11=0$

The roots are

$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$

$=\frac{-13\pm9}{4}$

$=-5.5, -1$

So, $m_1, m_2, m_3 = -1, -1, -5.5$

Then the general solution is :

$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$

8 0

3 years ago

Sorry but I need help AGAIN so sorry but help me plz

Dovator [93]

Answer:

no

Step-by-step explanation:

no.........................

8 0

3 years ago

Read 2 more answers

3x-6y=9<br> x=2y+3<br><br> SOMEONE HELP ME SOLVE THIS STEP BY STEP TY

RideAnS [48]

Answer:

0=0

infinitely many solutions

Step-by-step explanation:

plug x=2y+3 as x into 3x-6y=9...so

3(2y+3)-6y=9, which has our x=2y+3 plugged in because that is what x equals

if you solve its

6y+9-6y=9

0y=0

y=0

making it 0=0

you can't go further from this

6 0

3 years ago