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iris [78.8K]
3 years ago
7

HELP ME PLEASE I'LL GIVE U BRAINLIEST IF RIGHT!!

Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

1. is D

2. is A

Step-by-step explanation:

The Titanic could stay afloat with four of its 16 watertight compartments flooded, more than anyone could imagine on a ship of its size. ... As the ice bumped along its starboard side, it punched holes in the ship's steel plates, flooding six compartments. In a little over two hours, the Titanic filled with water and sank.

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What is the vertex of the absolute value function below?
Nonamiya [84]

Answer:

sry I just wanted the points I'm in middle school so I don't know this stuff either but can you give free brainlyest I'm soo close to my next rank I'd really appreciate it if you would

4 0
3 years ago
The length of the longer leg of a right triangle is 6 cm more than twice the length of the shorter leg. The length of the hypote
iragen [17]
Let x = the shorter leg
2x + 6 is the longer leg
2x + 9 is the hypotenuse

We now do the Pythagorean Theorem of a^{2}+b^{2} = c^{2}

x^{2} +  (2x+6)^{2} =  (2x+9)^{2}

Multiply out to get:

x^{2} +4 x^{2} +24x+36=4 x^{2} +36x+81

The 4 x^{2} will cancel out each other when you combine like terms to get all the terms on one side of the equal sign. 

Combine like terms with the rest to end with x^{2} -12x-45=0

Factor this to get (x-15)(x+3) = 0 then set each factor equal to zero. 

You end up with two solutions, x = 15 and x = - 3 HOWEVER distance cannot be measure in negatives so that answer will not work so x = 15. Now plug into our given information.

The short leg is 15 cm long.
The longer leg of 2(15) + 6 = 36 cm long
The hypotenuse of 2(15) + 9 = 39 cm long. 

You can check your answers by plugging them into the Pythagorean Theorem again. 
8 0
4 years ago
The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide a pin drop near one focus can clearly be
dedylja [7]

Answer:

Let the coordinate of focus be (\pm c , 0)

As per the statement: The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide.

⇒Length of Major axis=base of an auditorium = 200 feet and Length of a minor axis=wide of a auditorium = 100 ft

Semi-major axis (a) = 100 ft and

semi-minor axis(b) = 50 ft

Then, by an equation:

c^2 = a^2-b^2

Solve for c:

Substitute the given values we have;

c^2=(100)^2-(50)^2

Simplify:

c^2 = 7500

or

c=\sqrt{7500} = 86.6025404 ft

Distance between the foci is,  2c = 2 \cdot 86.6025404 = 173.205081

Therefore, the distance between the foci to the nearest 10th of a foot is, 173.2 ft

6 0
4 years ago
Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint.
inna [77]

Answer:

Hey there!

If the midpoint is (-5, 18) and the endpoint is (3, 13) the other endpoint is (-13, 23)

Let me know if this helps :)

8 0
3 years ago
PLEASE HELP WITH TRIG PROBLEM
Nimfa-mama [501]

Step-by-step explanation:

Angle G = 180° - 48° - 75° = 57°

By Sine rule, FG/sinD = DG/sinF = DF/sinG.

Hence DF = 22.57 units and DG = 25.99 units.

6 0
3 years ago
Read 2 more answers
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