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allsm [11]
2 years ago
6

A salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of ​$. Option

B is a commission rate of ​8% on weekly sales. How much does he need to sell this week to earn the same amount with the two​ options?
Mathematics
1 answer:
steposvetlana [31]2 years ago
3 0

Answer:

12500

Step-by-step explanation:

25 * 40 = 1000

8% of what = 1000?

8/100 x = 1000

x 12500

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Answer:

The last one

Step-by-step explanation:

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3 years ago
624/50<br> please help will give Brainliest!
natulia [17]
The answer is 12.48 hope this helps!
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If Denise has 3000 water bottles and gave 4x345 away, how many would she have left?
oee [108]
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5 0
3 years ago
General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
3 years ago
Cole said that 555 rounded to the nearest ten is 600. What's coles error?
ki77a [65]
Cole's mistake was that he rounded 555 to the nearest hundred instead of the nearest ten. He should've rounded it to 560 because the tens place is the second number, not the first one.
3 0
3 years ago
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