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creativ13 [48]
2 years ago
8

Please do this you will be marked brainliest

Mathematics
2 answers:
Alona [7]2 years ago
8 0

Answer: Z ≤ 12

The correct answer is "Z is less than or equal to 12", Z ≤ 12.

Step-by-step explanation:

Hope this helps.

mamaluj [8]2 years ago
5 0

Answer:

z ∈ { 12, + ∞ >

Alternate form: z ≥ 12, { z l z ≥ 12 }

Step-by-step explanation:

1- Determine the defined range

2- Factor the expression

3- Simplify the root

4- Move the variable to the left

5- Separate into possible cases

6- Solve

7- Find the intersections

8- Find the union

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Find the equation of this line.
lukranit [14]

Answer:

Shhshshsjjsjsjnsns

Step-by-step explanation:

Kaksmsndnndndnd

6 0
4 years ago
Can anyone help me ASAP please
Dmitry_Shevchenko [17]
Are you Muslim by any chance?
8 0
3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
NO LINKS!!!
matrenka [14]

Factor x^5 - x to get x(x^4 - 1) = x(x^2-1)(x^2+1) = x(x-1)(x+1)(x^2+1)

We see that x = 0, x = 1 and  x = -1 are the real number roots or x intercepts. Ignore the complex or imaginary roots. Unfortunately, the graph shows the x intercepts as -2, 0 and 2 which don't match up.

So there's no way that the given graph matches with f(x) = x^5-x.

-------------------

As more proof, let's consider the end behavior.

As x gets really large toward positive infinity, x^5 will do the same and so will x^5-x. Overall, f(x) will head off to positive infinity. Visually, moving to the right will have the graph move upward forever. This is the complete opposite of what is shown on the graph.

Likewise, the left endpoint should be aimed down instead of up. This is because x^5-x will approach negative infinity as x heads to the left.

In short, the graph shows a "rises to the left, falls to the right" end behavior. It should show a "falls to the left, rises to the right" pattern if we wanted to have a chance at matching it with x^5-x. Keep in mind that matching end behavior isn't enough to get a 100% match; however, having this contradictory end behavior is proof we can rule out a match.

I recommend using Desmos, GeoGebra, or whatever graphing program you prefer to plot out y = x^5-x. You'll get a bettter idea of what's happening.

8 0
3 years ago
Read 2 more answers
What is the product of 44(4-7)(4)?<br><br> 0 1/-16<br> 0 1/-8<br> 0 1/16<br> 0 1/8
valentina_108 [34]

Answer:

-528

Step-by-step explanation:

4-7=-3

44*-3*4=-132*4=-528

6 0
4 years ago
Read 2 more answers
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