What’s the slope of the graph

Please use a system of equations to solve this problem. I already know how to solve this, but I want to know how to solve it usi

DiKsa [7]

Answer:

$\boxed{\sf \ \ \ 15 \ \ novelists \ \ and \ \ 9 \ \ poets \ \ \ }$

Step-by-step explanation:

hello,

let's note a the number of novelists and

b the number of poets.

we know that a = 5/3 b as "enrolls novelits and poets in a ratio of 5:3"

it comes 3a=5b which is the first equation

and we know that a + b = 24 "there are 24 people"

we we have two equations

(1) 3a - 5b = 0

(2) a + b = 24

let's multiply (2) by 3 it comes 3a + 3b = 24*3 = 72

let's do 3*(2) - (1) it comes

3a + 3b -3a + 5b = 72 - 0 = 72

so 8b = 72

so b = 9

and then we replace b in (2) it comes

a = 24-9 = 15

hope this helps

3 0

3 years ago

Please help on number 9,

sergejj [24]

Answer:

50

Step-by-step explanation:

9. There are 4 odd numbers and 4 even numbers

P(odd number) = odd numbers/ total

= 4/ (4+4)

=4/8

= 1/2

If we spin 100 times, we multiply the number of times we spin * the probability

100 * 1/2 = 50

3 0

3 years ago

The U.S. public debt as of October 2010 was $9.06 × 1012. What was the average U.S. public debt per American if the population i

Fofino [41]

Answer-

The average U.S. public debt per American is approximately $29,400

Solution-

Given in the question,

U.S public debt as of October 2010 = $9.06×10¹²

Population of U.S in 2010 = 3.08×10⁸

We have to calculate the average U.S. public debt per American,

$\text{Average debt per American}=\frac{\text{Total debt}}{\text{Population}}\\\\=\frac{9.06\times 10^{12}}{3.08\times 10^8}\\\\=2.9415\times 10^{(12-8)}\\\\=2.9415\times 10^4 \approx 2.94\times 10^4=29,400$

Therefore, the average U.S. public debt per American is $29,400 (after rounding off)

6 0

3 years ago

Andy is considering taking a loan to remodel his kitchen. He is offered a loan by his bank for five years and an annual interest

Aleksandr-060686 [28]

Using compound interest, it is found that the maximum amount of money he can borrow is of $8,700.

------------------------

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal).
n is the number of times that interest is compounded per year.
t is the time in years.

Maximum monthly payments of $200 per month per five years, thus:

$A(t) = 5 \times 200 \times 12 = 12000$

Interest rate of 6.5%, thus $r = 0.065$ .
Monthly payments, thus $n = 12$ .
Five years, thus $t = 5$ .
The amount he can borrow is the principal.

$A(t) = P(1 + \frac{r}{n})^{nt}$

$12000 = P(1 + \frac{0.065}{12})^{60}$

$1.38282P = 12000$

$P = \frac{12000}{1.38282}$

$P = 8678$

To the nearest 100, $8,700.

The maximum amount of money he can borrow is of $8,700.

A similar problem is given at brainly.com/question/15340331

5 0

3 years ago

In a study to find the proportion of children with asthma in a certain population, we desire a 95% confidence interval with stan

soldier1979 [14.2K]

Answer:

The minimum sample size should be of 381.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Without any prior knowledge of the proportion, what should be our minimum sample size

We dont know the population proportion, so we use $\pi = 0.5$ , which is when the largest sample size is needed. We have to find n for which $M = 0.05$ . So