Answer:
all the numbers +
Step-by-step explanation:
V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>
Given expression ,
We know that, ![a^{\frac{m}{n}} = \sqrt[n]{a^m}](https://tex.z-dn.net/?f=%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20)
Therefore , this can be written as ,
![\implies \sqrt[4]{13^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B4%5D%7B13%5E3%7D%20)
<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>
Given expression ,
![\implies \sqrt[3]{24^{10}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7B24%5E%7B10%7D%7D%20)
We know that,
Therefore, this can be written as ,
Answer: option J: 128 joules
Explanation:
1) From the table you try to find which relation best fits the data.
2) Your best first assumption is that the data may fit a proportional relation.
3) To prove that you find the ratio of Energy ouput to Amount of chemicals.
Doing that you find:
20 32 48 60
----- = ------- = ------ = ------ = 4
5 8 12 15
4) Then you have found a direct relation whose ratio is 4 joules / mol. So, you can apply that constant to the number of moles given:
Energy = 4 joules / mol × 32 mol = 128 joules
