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2 years ago

8

( -2 ) × (4.5) equals

2 answers:

mamaluj [8]2 years ago

8 0

Answer: -9

Step-by-step explanation:

Hope this helps. have a nice day <33

KatRina [158]2 years ago

3 0

Answer:

-9

Step-by-step explanation:

A negative times a positive make a negative outcome. (Using rule of integers)

2×4.5=9

Make it negative to get -9

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According to the scale on a road map, 3 cm represents 45 kilometers. if two cities measure 10 cm apart on the map, how many kilo

denpristay [2]

150 Km.

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3 years ago

30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

3 years ago

Sold 12 rolls of wrapping paper and 21 ribbon for $143.25. Then 16 rolls of wrapping paper and 25 ribbon for $181.25. How much i

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Answer:

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Step-by-step explanation:

3 0

3 years ago

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

ElenaW [278]

$\huge\boxed{y-5&=-\frac{1}{3}(x+9)}$

First, we'll find the slope of the new line. The first line has a slope of $3$ . Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by $-1$ ) to get $-\frac{1}{3}$ for the new slope.

Then, we'll use the point-slope form to make the new equation, where $m$ is the slope and $(x_1,y_1)$ is a point on the line:

$\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}$

3 0

2 years ago

Read 2 more answers

Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio

andrey2020 [161]

Answer:

$19-\dfrac{28}{n}$ is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

$43-5n$

Substituting the value of n,

$43-5\left(7\right)$

Simplifying,

$43-35=8$

Since the value of the expression is 8 which is not equal 15.

Hence expression $43-5n$ does not have value of 15 when n = 7.

Expression 2:

$3n-5$

Substituting the value of n,

$3\left(7\right)-5$

Simplifying,

$21-5=16$

Since the value of the expression is 16 which is not equal 15.

Hence expression $3n-5$ does not have value of 15 when n = 7.

Expression 3:

$6n-28$

Substituting the value of n,

$6\left(7\right)-28$

Simplifying,

$42-28=14$

Since the value of the expression is 14 which is not equal 15.

Hence expression $6n-28$ does not have value of 15 when n = 7.

Expression 4:

$19-\dfrac{28}{n}$

Substituting the value of n,

$19-\dfrac{28}{7}$

Simplifying,

$19-4=15$

Since the value of the expression is 15 which is equal 15.

Hence expression $19-\dfrac{28}{n}$ has the value of 15 when n = 7.

4 0

3 years ago

Read 2 more answers